实现一个Promise之基础、异步
其实跟着promise a+一步一步,按照顺序实现一个promise并不难,今天先实现最简单的promise和异步resolve。本来想全部一次性写完,想想还是分开走,希望想学的可以敲几遍。
//promise三个状态
const PENDING = 'PENDING';
const FULFILLED = 'FULFILLED';
const REJECTED = 'REJECTED';
class Promise {
constructor(executor){
//状态
this.state = PENDING;
//成功值 失败值 默认undefined
this.value = undefined;
this.reason = undefined;
//简易发布订阅,实例可以then多次,用数组
this.onResolvedCallbacks = [];
this.onRejectedCallbacks = [];
//成功方法
let resolve = (value) => {
if(this.state === PENDING){
this.state = FULFILLED;
this.value = value;
this.onResolvedCallbacks.forEach(fn => fn());
}
};
//失败方法
let reject = (reason) => {
if(this.state === PENDING){
this.state = REJECTED;
this.reason = reason;
this.onRejectedCallbacks.forEach(fn => fn());
}
};
//立即执行,如果有错误直接执行失败方法
try{
executor(resolve, reject);
}catch (e) {
reject(e);
}
}
//then方法,一个成功函数,一个失败函数
then(onFulfilled, onRejected){
//如果成功,执行成功函数
if(this.state === FULFILLED){
onFulfilled(this.value);
};
//如果失败,执行失败函数
if(this.state === REJECTED){
onRejected(this.reason);
};
//如果有异步,订阅成功失败函数
if(this.state === PENDING){
this.onResolvedCallbacks.push(() => {
onFulfilled(this.value);
});
this.onRejectedCallbacks.push(() => {
onRejected(this.reason);
});
};
}
}
最简单的实现,可以理解理解。
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